（转）jquery serialize表单序列化，当radio或checkbox 未选中时，没有序列化到对象中的原因分析和解决方案 - ghostsf

jQuery.fn.extend({
    serialize: function() {
        return jQuery.param( this.serializeArray() );
    },
    serializeArray: function() {
        return this.map(function() {
            // Can add propHook for "elements" to filter or add form elements
            var elements = jQuery.prop( this, "elements" );
            return elements ? jQuery.makeArray( elements ) : this;
        })
        .filter(function() {
            var type = this.type;
            // Use .is( ":disabled" ) so that fieldset[disabled] works
            return this.name && !jQuery( this ).is( ":disabled" ) &&
                rsubmittable.test( this.nodeName ) && !rsubmitterTypes.test( type ) &&
                ( this.checked || !rcheckableType.test( type ) );
        })
        .map(function( i, elem ) {
            var val = jQuery( this ).val();
            return val == null ?
                null :
                jQuery.isArray( val ) ?
                    jQuery.map( val, function( val ) {
                        return { name: elem.name, value: val.replace( rCRLF, "\r\n" ) };
                    }) :
                    { name: elem.name, value: val.replace( rCRLF, "\r\n" ) };
        }).get();
    }
});

//为jquery.serializeArray()解决radio,checkbox未选中时没有序列化的问题
    $.fn.ghostsf_serialize = function () {
        var a = this.serializeArray();
        var $radio = $('input[type=radio],input[type=checkbox]', this);
        var temp = {};
        $.each($radio, function () {
            if (!temp.hasOwnProperty(this.name)) {
                if ($("input[name='" + this.name + "']:checked").length == 0) {
                    temp[this.name] = "";
                    a.push({name: this.name, value: ""});
                }
            }
        });
        //console.log(a);
        return jQuery.param(a);
    };